Reports are that ICE arrested 308 Illegals yesterday, so I did a little math...
To calculate how many days it would take to deport 10,000,000 immigrants at a rate of 308 per day, you divide the total number of immigrants by the deportation rate:
\text{Number of days} = \frac{10,000,000}{308}
Let's do the math:
\frac{10,000,000}{308} \approx 32,467.53
Therefore, it would take approximately 32,468 days to deport 10 million immigrants at a rate of 308 per day.
To convert this into years:
\text{Number of years} = \frac{32,468 \text{ days}}{365 \text{ days/year}} \approx 88.95 \text{ years}
So, it would take roughly 89 years to deport 10 million immigrants if the rate remains constant at 308 deportations per day.
Here is how many they need to deport / day to get back to where we were before biden took office, assuming the number of illegals is around 10 million, which I think is probably a low estimate.
To determine how many people would need to be deported per day, excluding weekends and holidays, over 4 years to deport 10 million people, we'll follow these steps:
- Calculate Total Working Days in 4 Years:
- There are 365 days in a year.
- Over 4 years, there are 4 * 365 = 1,460 days.
- However, we need to exclude weekends (which are 104 per year, or 416 over 4 years) and holidays. Assuming there are about 10 federal holidays per year in the U.S. (so 40 over 4 years), we subtract these from the total days.
Total working days:
1,460 - 416 (\text{weekends}) - 40 (\text{holidays}) = 1,004 \text{ working days}
- Calculate Deportations per Day:
- We need to deport 10 million people in 1,004 working days.
Deportations per day:
\frac{10,000,000}{1,004} \approx 9,960.16
Since you can't deport a fraction of a person, we'll round up to the next whole number:
\text{Deportations per day} = 9,961
Therefore, you would need to deport approximately 9,961 people per working day, excluding weekends and holidays, to complete the task in 4 years.